$\cos\, \frac{\pi}{6}=\frac{1}{2}$
Vrai
Faux
$\sin\, \frac{\pi}{3}=\frac{1}{2}$
$\sin(-a)=-\sin a$
$\mbox{tg }\, \frac{\pi}{6}=\frac{\sqrt{3}}{3}$
$\sin^2{a}=1+\cos^2{a}$
$\cos{(\pi-a)}=\sin{a}$
$\cos\, \frac{\pi}{4}=\frac{1}{2}$
$\mbox{tg }\frac{\pi}{2}=0$
$\cos{(a+b)}=\cos{a}\cos{b}+\sin{a}\sin{b}$
$\mbox{tg }(-a)=\mbox{tg }a$